Physics Problem - A spring is fixed vertically to the floor

A #spring is fixed #vertically to the floor.
A 10-kg #box is then #pressed down such that the spring is #compressed https://t.co/Z5fLcbq2LX

— Physics I (@PHY210) October 5, 2016

A spring is fixed vertically to the floor.
A 10.0-kg box is then pressed down such that the spring is compressed 0.500 m beyond its equilibrium length.
The box is then released and it travels vertically upward to a maximum height of 2.40 m above its release point.
Assuming the work done against drag (air resistance) is 120. J, what is the spring constant of the spring?
Given Data:
M= 10.0-kg
x= 0.5 m
h=2.40 m
Wᵣ =120 J
k=?
Solution:
½kx²=mgh+Wᵣ Law of Energy Conservation
k=2(mgh+Wᵣ )/x² Symbolical Solution
2*(10kg*9.82m/s^2*2.40m+120J)/(0.5m)^2 in N/m Code of Google Calculator
2845.44 N / m Google Calculator's result
k=2840 N/m