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Яндекс.Метрика

Friday, September 30, 2016

Problem from Quiz 5

A train with the mass M accelerates uniformly from the rest to the speed V when passing through a distance d
What is its kinetic energy
when it passing through a distance
d (d < d)?

Given Data: M = 15,000 kg
V = 0
V = 15 m / s
d = 150 m
d = 75 m
K = ?
Solution:
K(kinetic energy) = K(kinetic energy initial) + W(work) = W
W = Fx
K = W = Fd = ½MV²
F = ½MV² / d
K = W = Fd = ½MV² d / d
K = ½(15,000 kg)(15 m/s)² (75m) / (150m) = 843750 J

Google Calculator Code:
0.5*(15000 kg)*(15 m/s)^2*(75m) / (150m)


Answer: 840 kJ

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