A
train with the mass M
accelerates uniformly from the rest to the speed V
when passing through a distance d.
What is its kinetic energy
when it passing through a distance d₁ (d₁ < d)?
when it passing through a distance d₁ (d₁ < d)?
Given
Data: M = 15,000
kg
Vₒ
= 0
V
= 15
m / s
d
= 150
m
d₁
= 75
m
K₁
=
?
Solution:
K(kinetic
energy) = Kₒ(kinetic
energy initial) + W(work)
= W
W
= Fx
K
= W
= Fd
= ½MV²
F
= ½MV²
/ d
K₁
=
W₁
=
Fd₁
=
½MV²
d₁
/
d
K₁
= ½(15,000
kg)(15
m/s)²
(75m)
/
(150m) = 843750
J
Google
Calculator Code:
0.5*(15000
kg)*(15
m/s)^2*(75m)
/
(150m)
Answer:
840
kJ
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